Day8-169. Majority Element

今日题目：169. Majority Element(easy)

Given an array nums of size n, return the majority element.
The majority element is the element that appears more than ⌊n / 2⌋ times. You may assume that the majority element always exists in the array.

Example 1:
Input: nums = [3,2,3]
Output: 3

Example 2:
Input: nums = [2,2,1,1,1,2,2]
Output: 2

Constraints:

• n == nums.length
• 1 <= n <= 5 * 104
• -231 <= nums[i] <= 231 - 1
  Follow-up: Could you solve the problem in linear time and in O(1) space?

My solution

class Solution:
    def majorityElement(self, nums: List[int]) -> int:
        nums.sort()
        return nums[len(nums)//2]

Result