Assume you are an awesome parent and want to give your children some cookies. But, you should give each child at most one cookie.
Each child i has a greed factor g[i]
, which is the minimum size of a cookie that the child will be content with; and each cookie j
has a size s[j]
.
If s[j]
>= g[i]
, we can assign the cookie j
to the child i
, and the child i
will be content.
Your goal is to maximize the number of your content children and output the maximum number.
Example 1:
Input: g = [1,2,3], s = [1,1]
Output: 1
Explanation: You have 3 children and 2 cookies. The greed factors of 3 children are 1, 2, 3.
And even though you have 2 cookies, since their size is both 1, you could only make the child whose greed factor is 1 content.
You need to output 1.
Example 2:
Input: g = [1,2], s = [1,2,3]
Output: 2
Explanation: You have 2 children and 3 cookies. The greed factors of 2 children are 1, 2.
You have 3 cookies and their sizes are big enough to gratify all of the children,
You need to output 2.
Constraints:
有一串小孩的胃口,和另一串饼乾数量。要满足最多小孩的胃口
看到这种满足OO、让最多XX怎样怎样的题目,直觉就是使用贪婪演算法
class Solution:
def findContentChildren(self, g: List[int], s: List[int]) -> int:
g.sort()
s.sort()
# 可以喂饱的小孩数量
res = 0
# 遍历所有饼乾
for i in range(len(s)):
# 如果可喂饱的数量小於小孩总数,且饼乾大小大於下一个小孩的胃口。则喂饱数量 +1
if res < len(g) and s[i] >= g[res]:
res += 1
else:
break
return res
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