题目连结:https://leetcode.com/problems/find-the-difference/
题目重点:t字串大於s字串,只随机多"一个"字母。
2.7.3 :048 > "a".bytes
=> [97]
2.7.3 :049 > "a".ord
=> 97
2.7.3 :050 > "aa".bytes
=> [97, 97]
2.7.3 :051 > "aa".ord
=> 97
2.7.3 :052 > [97, 97].sum
=> 194
2.7.3 :053 > "aa".sum
=> 194
def find_the_difference(s, t)
(t.sum - s.sum).chr
end
2.7.3 :054 > 99.chr
=> "c"
def find_the_difference(s, t)
#s与t先转换成有序阵列
#一个一个比较,回array内那个不相同的
end
2.7.3 :058 > "acade".chars
=> ["a", "c", "a", "d", "e"]
2.7.3 :059 > "acade".split""
=> ["a", "c", "a", "d", "e"]
2.7.3 :060 > ["a", "c", "a", "d", "e"].sort
=> ["a", "a", "c", "d", "e"]
ans
def find_the_difference(s, t)
s_arr = s.chars.sort
t_arr = t.chars.sort
i = 0
while i < t.length
if t_arr[i] != s_arr[i]
return t_arr[i]
else
i += 1
end
end
end
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